2x^2+2y^2+4x-8y=12

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Solution for 2x^2+2y^2+4x-8y=12 equation: 


Simplifying
2x2 + 2y2 + 4x + -8y = 12

Reorder the terms:
4x + 2x2 + -8y + 2y2 = 12

Solving
4x + 2x2 + -8y + 2y2 = 12

Solving for variable 'x'.

Reorder the terms:
-12 + 4x + 2x2 + -8y + 2y2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 4x + 2x2 + -8y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-6 + 2x + x2 + -4y + y2) = 0

Ignore the factor 2.

Subproblem 1
Set the factor '(-6 + 2x + x2 + -4y + y2)' equal to zero and attempt to solve:

Simplifying
-6 + 2x + x2 + -4y + y2 = 0

Solving
-6 + 2x + x2 + -4y + y2 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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